Question: Two station A and B are 110
km apart on a straight line. A train starts from A at 8 a.m. and travels
towards B at the rate of 40 km/hr. 2 hours later another train starts from B
and travel towards A at the rate of 50 km/hr. When will the first train meet to
the second train? [Ans. (d) 10:20 A.M.]
(a) 11 am (b) 9 am
(c) 10.15 am (d) 10.20 am (e) None of these
Detailed
explanation:
Concept: 1.
“Relative speed is used, when both the body move to start at the same time.”
2. “When the bodies are moving
in the opposite directions, the relative speed is the sum of the speeds”
Two station A
and B are 110 km apart on a straight line. A train starts from A at 8 a.m. and
travels towards B at the rate of 40 km/hr. So, the distance described in 2 hrs
is 40×2 = 80 km and the train reaches at C at 10 AM.
2 hours later
another train starts from B and travel towards A at the rate of 50 km/hr.
Relative speed
= (40 + 50) km/h = 90 km/h
Distance = (110
– 80) km = 30 km
Time taken by
two trains to meet = 30 km/90 km/h = 1/3 hour = 20 minutes
Therefore, the
first train meet to the second train at 10:20 AM Ans.
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