Question: A bag
contains 7 blue balls and 5 yellow balls. If two balls are selected at random,
what is the probability that none is yellow? [Ans. (3) 7/22 ]
(1) 5/33 (2) 5/22 (3) 7/22 (4) 7/33 (5) 7/66
Solution:
Concept:
Probability:
Probability of an event is defined as the ratio of no. of favorable cases to
the no. of all possible outcomes. In other words, it is the ratio of n (E) and
n (S).
P (E) = n (E)/n (S)
(1) 0 < P (E) <
1
(2) P (E) + P (E’)
= 1
Detailed Explanation:
A bag contains 7 blue balls and 5 yellow balls. Here, total number of balls is
7+5 = 12, out of which two balls are to be selected at random. So, total no. of
outcomes is 12C2.
Since none of the two
balls drawn should be yellow, this means, both should be blue. Total no. of
blue balls is 7. So, no. of combinations is 7C2.
Therefore,
probability can be find out as
7C2 7×6 7
Probability = ------ = ------- = ------ Ans.
12C2 12×11 22
==============================================================================================================================================
No comments:
Post a Comment