Question: A and B can do a piece of work in 12 days, B
and C in 15 days, C and A in 20 days. In how many days can all of A, B and C
together finish the whole work? [Ans. (b) 10 days]
(a) 20 days
(b) 10 days (c) 5 days (d) 12 days
(e) None of these
Solution:
Detailed Solution: Given
that A + B can do a work in 12 days; B + C can do it in 15 days and C + A can
do the same work in 20 days.
First Method: (A + B), (B + C) and (C + A) can do the
same work in 1/[1/x+1/y+1/z] days
So, 2 (A + B + C) can do the work in1/[1/12
+1/15 +1/20] days =
60/[5+4+3] days = 60/12 days
= 5 days.
Therefore, (A + B + C) can finish the whole
work in 5×2 = 10 days. Ans.
Second Method: (A + B), (B + C) and (C + A) can do the
same work in xyz/[xy + yz + zx] days
So, 2 (A + B + C) can do a work in [12 × 15 × 20]/[12×15 + 15×20 +20 ×12] = 5 days
Therefore, (A + B + C) can finish the whole
work in 5×2 = 10 days. Ans.
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