Tuesday, 30 June 2015

PROBLEMS BASED ON AGES–03

Question: The sum of the ages of a mother and her daughter is 50 years. Also, 5 years ago, the mother’s age was 7 times the age of the daughter. What are the present ages of the mother and the daughter? [एक माता और उसकी पुत्री की उम्रों का योगफल 50 वर्ष है. 5 वर्ष पहले माता की आयु पुत्री की आयु की 7 गुणी थी. बताएं कि आज माता और पुत्री की आयु क्या है?]  [Ans. (c) 40 yrs, 10 yrs]                                     
(a) 45 yrs, 5 yrs   (b) 42 yrs, 8 yrs  (c) 40 yrs, 10 yrs (d) 41 yrs, 9 yrs (e) none of these          


Solution:
Detailed Explanation:
Concept: When the sum of the ages of two persons goes to 5 years ago, it is reduced by 10 years (as the age of each of the persons is reduced by 5 years)

First Method: Given that the sum of the ages of a mother and her daughter is 50 years (at present), so the sum of their ages 5 years ago was 50-10 = 40 years.

Also given that the ratio of the ages of the mother and her daughter 5 years ago was 7:1, so that the sum is 8 (in terms of ratio). 

8 ≡ 40 years
1 ≡? = 5 years (the age of daughter 5 years ago)
7 ≡? = 35 years (the age of mother 5 years ago)

Therefore, the present age of mother is 35+5 = 40 years and the present age of daughter is 5+5 = 10 years. Ans.

Second Method: Let the ages of daughter and mother 5 years ago were “x” years and “7x” years.  So, their present ages are respectively (x+5) years and (7x+5) years.

Given that the sum of the present ages of mother and her daughter is 50 years, so
(7x+5) + (x + 5) = 50 or, 8x = 40 or, x = 5

Therefore, the present age of mother = 7×5+5 = 40 yrs and the present age of daughter = 5+5 = 10 yrs Ans.   


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