Basic Calculation:17

Multiplication of two numbers having base 100

102 × 105  = [(102+5) ×100 + (2×5)] = 10710

103 × 109  = [(103+9) ×100 + (3×9)] = 11227

104 × 107  = [(104+7) ×100 + (4×7)] = 11128

102 × 108  = [(102+8) ×100 + (2×8)] = 11016

101 × 109  = [(101+9) ×100 + (1×9)] = 11009

106 × 111  = [(106+11) ×100 + (6×11)] = 11766

108 × 112  = [(108+12) ×100 + (8×12)] = 12096

103 × 122  = [(103+22) ×100 + (3×22)] = 12566

111 × 113  = [(111+13) ×100 + (11×13)] = 12543

112 × 114  = [(112+14) ×100 + (12×14)] = 12768

Detailed Explanation: Multiplication of two numbers having the base 100 and the numbers are more than 100.

Rule is that the one of the numbers is how much above the other number, which is added to the other number.

For example, in the multiplication of 102 × 105, 102 is 2 more than 100, so 2 is added to the other number 105; so that it becomes 102+5 = 107 and we read it as 107 hundreds. Then, we see that the two numbers are how much above the base 100. We multiply them and add. So, the answer is 107 hundred and 10 = 10710. Ans.

Similarly, in the product of 103 × 109; 103 and 109 are above by 3 and 9 respectively, so either 3 is added to 109 or 9 is added to 103, it becomes 112. And, 3×9 = 27. So, the answer is 11227.